X^2=1x+14

Solution for X^2=1x+14 equation:

X^2=1X+14

We move all terms to the left:

X^2-(1X+14)=0

We add all the numbers together, and all the variables

X^2-(X+14)=0

We get rid of parentheses

X^2-X-14=0

We add all the numbers together, and all the variables

X^2-1X-14=0

a = 1; b = -1; c = -14;
Δ = b2-4ac
Δ = -12-4·1·(-14)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{57}}{2*1}=\frac{1-\sqrt{57}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{57}}{2*1}=\frac{1+\sqrt{57}}{2}
$